Answer:
The cannonball will be at the highest point in 9.375 seconds after the shot.
Step-by-step explanation:
Suppose we have a quadratic function in the format:
\(y(t) = at^{2} + bt + c\)
The maximum point will happen when:
\(t_{v} = -\frac{b}{2a}\)
The point will be:
\(y_{MAX} = y(t_{v})\)
In this problem:
\(y = -16t^{2} + 300t\)
So \(a = -16, b = 300\)
We have to find \(t_{v}\)
\(t_{v} = -\frac{300}{2(-16)} = 9.375\)
The cannonball will be at the highest point in 9.375 seconds after the shot.
