Answer:
The work is 9.99J.
Explanation:
The work associated with a process is given by the following formula:
\(W = P*\Delta\)
In which W is the work, P is the pressure and \(\Delta\) is the difference of volume.
In this problem, we have that:
The volume of an ideal gas is decreased from 5.0 l to 5.0 ml. Each ml has 0.001l. So the volume of the ideal gas is decreased from 5.0l to 0.005l. So
\(\Delta = 4.995\).
Constant pressure of 2.0 atm. So \(P = 2\).
\(W = P*\Delta\)
\(W = 2*4.995\)
\(W = 9.99\)
The work is 9.99J.
