Verified Answer :

Answer:The electric force between them is \(1.024\times 10^{-17} N\).

Explanation:

Charge on an electron = \(q_1=q_2=-1.6\times 10^{-19} C\)

Distance between the two electrons = \(r=1.5\times 10^{-10} m\)

The Electric force between two electrons is given by :

\(F_e=k\times \frac{q_1\times q_2}{r^2}\)

\(F_e=9\times 10^9 N m^2/C^2\times \frac{-1.6\times 10^{-19} C\times -1.6\times 10^{-19} C}{(1.5\times 10^{-10} m)^2}=1.024\times 10^{-17} N\)

The electric force between them is \(1.024\times 10^{-17} N\).

Eduard22sly

The electric force between the two electrons is 1.024×10¯⁸ N

Data obtained from the question

  • Distance apart (r) = 1.5×10¯¹⁰ m
  • Electrical constant (K) = 9×10⁹ Nm²/C²
  • Charge of electron = q₁ = q₂ = 1.6×10¯¹⁹ C
  • Force (F) =?

How to determine the force of attraction between the two electrons

F = Kq₁q₂ / r²

F = (9×10⁹ × 1.6×10¯¹⁹ × 1.6×10¯¹⁹) / (1.5×10¯¹⁰)²

F = 1.024×10¯⁸ N

Thus, the force between them is 1.024×10¯⁸ N

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