Sine ratio for an acute angle of a right triangle always be a positive value less than 1.
In a right angled Δ ABC, sine of angle \(\theta\) can be written as:
\(\rm Sin \; \theta = Perpendicular /Hypotenuse\)
Therefore,
\(\rm Sin \; \theta =AB/AC\)
Please refer to the diagram that is uploaded in the solution.
The Pythagoras theorem can be used to determine the unknown value in a right triangle from two known values.
Thus, the formulated way to represent the theorem for hypotenuse is given below:
\(\rm H = \sqrt{( P^2 + B^2) } .....(1)\)
Hence,
Hypotenuse is the longest side of the Right triangle and therefore its value must be greater than zero and should always be more than perpendicular.
Thus,
\(\rm Hypotenuse > 0 \; and\; Hypotenuse > Perpendicular\)
\(\rm Sin \theta = \dfrac{Perpendicular }{Hypotenuse} <1\)
so, we can say that \(\rm Sin\theta\) is always positive and less then 1.
For more information please refer to the link below
https://brainly.com/question/15141309
