Answered

1.What are the zeros of the polynomial function?

f(x)=x^2+9x+20

2.What are the zeros of the polynomial function?

f(x)=x^2−4x−60


3.What are the roots of the equation?

x^2+24=14x


4.What are the zeros of the function?

g(x)=x^2−x−72

Verified Answer :

  1. X^2+9x+20
    =x^2+(4+5)x+20
    =x^2+4x+5x+20
    =x(x+4)+5(x+4)
    =(x+4)(x+5)
    So zeroes are -4 and -5

    2.x^2-4x-60
    =x^2-(10-6)x-60
    =x^2-10x+6x-60
    =x(x-10)+6(x-10)
    =(x-10)(x+6)
    So zeroes are 10 and -6

    3.x^2+24=14x
    =x^2-14x+24
    =x^2-(12+2)x+24
    =x^2-12x-2x+24
    =x(x-12)-2(x-12)
    =(x-12)(x-2)
    So zeroes are 12 and 2

    4.x^2-x-72
    =x^2-(9-8)x-72
    =x^2-9x+8x-72
    =x(x-9)+8(x-9)
    =(x-9)(x+8)
    So the zeroes are 9 and -8

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