Find the area of a regular hexagon with the given measurement. 4-inch side A = sq. in. Please show work.
Answer:
The area of hexagon is 41.57 inch².
Step-by-step explanation:
The formula for area of regular hexagon is
\(A=\frac{3\sqrt{3}}{4}a^2\)
Where, a is the side length of regular hexagon.
It is given that the length of side is 4 inch.
The area of regular hexagon is
\(A=\frac{3\sqrt{3}}{4}\times(4)^2\)
\(A=\frac{3\sqrt{3}}{2}\times 16\)
\(A=3\sqrt{3}\times 8\)
\(A=24\sqrt{3}\)
\(A=41.57\)
Therefore the area of hexagon is 41.57 inch².
Answer:
\(A=41.58(inches)^2\)
Step-by-step explanation:
Given: The side of the regular hexagon measures 4 inches.
To find: The area of the regular hexagon.
Solution: The area of the regular hexagon can be found as:
\(A=\frac{3\sqrt{3}}{2}(side)^2\)
\(A=\frac{3\sqrt{3}}{2}(4)^2\)
\(A=\frac{3\sqrt{3}}{2}(16)\)
\(A=24\sqrt{3}\)
\(A=41.58(inches)^2\)
Thus, the area of the regular hexagon will be equal to \(41.58 (inches)^2\).