lindseyhajdukovich
Answered

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?


Which of the following equations is used in the process of solving this problem?

Ax^2 - 7x + 70 = 0
Bx^2 - 7x + 10 = 0
Cx^2 + 7x - 10 = 0

Verified Answer :

apologiabiology

x^2=-10+7x
x^2-7x+10=0

B is answer

The answer is possibly B

Related Questions