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tyger
tyger tyger
  • 18-02-2017
  • Chemistry
Answered

Only someone who truly knows and understands this, please tell me if the electron configurations are right :


Cobalt= [Ar] 4s^2 3d^7

Gallium= [Ar] 3d^10 4s^2 4p^1

Rhodium= [Kr] 4d^8 5s^1

Lanthanum= [Xe] 5d^1 6s^2

Europlum= [Xe] 4f^7 6s^2

Thulium= [Xe] 6s^2 4f^13

ytterblum= [Xe] 6s^2 4f^14

polonlum= [Xe] 6s^2 4f^14 5d^10 6p^4

Curium= [Rn] 5f^7 6d^1 7s^2

Rutherfordium= [Rn} 5f^14 6d^2 7s^2

Verified Answer :

luiscamacho
luiscamacho luiscamacho
  • 18-02-2017

yes is 4s^23d^7=cobalt

Answer Link

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