{y = 3x -1{x-y = - 9
always make sure both the equations have equal notations so 3x-y=1 and x-y=0after the that u may use the normal simultaneous eqn and find values of x and y
Here, substitute the value of y from equation 1 into equation 2, x - y = -9x - (3x - 1) = -9x - 3x + 1 = -9-2x = -9 - 1x = -10/-2x = 5Now, substitute the value in 1st equation, y = 3(5) - 1 y = 15 -1 = 14In short, Your Answer would be: (5, 14)Hope this helps!