For this case we have the following expression:
\(\frac{1}{8} + \frac{1}{4}\)
To make the addition more easily, we can rewrite the expression so that we have the same denominator in both terms.
We have then:
\(\frac{1}{8} + \frac{1}{4} =\frac{1}{8} + \frac{1}{4}.\frac{2}{2}\)
\(\frac{1}{8} + \frac{1}{4} =\frac{1}{8} + \frac{2}{8}\)
Since we have the same denominator, we can add the numerators and place the same denominator.
We have then:
\(\frac{1}{8} + \frac{1}{4} = \frac{1+2}{8}\)
\(\frac{1}{8} + \frac{1}{4} = \frac{3}{8}\)
Answer:
The total sum is given by:
\(\frac{1}{8} + \frac{1}{4} = \frac{3}{8}\)
