Mr. jones has blood type b and mrs. jones has blood type ab. what is the probability that they will have a child with blood type a if both of mr. jones’s parents were ab?

A0%.
B25%.
C50%.
D100%.

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Verified Answer :

Anonymous Anonymous · Answer 1 · 2017-02-19T05:47:08-05:00

Cross: Ib Ib × Ia Ib

Offspring: IaIb , IbIb, IaIb, IbIb

ab = 50%
b = 50%
a = 0%

In short, Your Answer would be Option A) 0%

Hope this helps!

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JoiePatel JoiePatel · Answer 2 · 2019-01-03T06:40:15-05:00

Answer:

The correct answer would be a. 0%

Mr. Jones has blood group B and that of their parents was AB. Thus, he must be homozygous for blood group B that is, \(I^{B}I^{B}\).

Then, he would only produce one type of gamete, \(I^{B}\).

The blood group of Mrs. Jones is AB. Thus, the genotype of her gene would be \(I^{A}I^{B}\).

Hence, she would produce two types of gametes, one containing \(I^{A}\) and other containing \(I^{B}\).

The cross would result in the production of children with two types of genotypes \(I^{A}I^{B}\) and \(I^{B}I^{B}\).

Thus, the phenotype of children can be either blood group AB or blood group B.

Hence, the probability of a child having a blood group A would be 0%.