Answer:
x has 2 values: \(x_{1}=3 + \sqrt{26} *i\) , \(x_{2} = 3 - \sqrt{26}*i\)
Step-by-step explanation:
First: Rearrange the equation to get 0 as a result.
(In this case: \(x^{2} -6x + 42-7 = 0\)
that can be reduced to: \(x^{2} -6x+35=0\))
Second: Apply the quadratic equation formula \(x = \frac{-b±\sqrt{b^{2}-4*a*c }}{2*a}\)
For a= 1 ; b= -6 ; c= 35.
Third: Replace & solve to find \(x_{1}\) and \(x_{2}\) :
\(\frac{6±\sqrt{-104}}{2*1}\) (Note: \(\sqrt{-104} = 2*\sqrt{-26}\))
And replacing \(\sqrt{-1} = i\):
\(x_{1} = 3+\sqrt{26}*i\) and \(x_{2} = 3-\sqrt{26}*i\)
Note: If a character  appears, just ignore it (it is an error in the insertion of the formulas, it has no effect on the results)
