\(\frac{2}{3}\)
\(\frac{2}{3} (9) - x \ \textless \ ?\)
\(\frac{2(9) - x}{3} - 3 \ \textless \ ?\)
\(\frac{3(3)}{3}\)
\(\frac{9 - 2(x)}{3}\) < ?
First: Multiply the number 3 on your sides
Second: Multiply again but by negative 1 {-1}
You have to flip your inquality sign since we multiplied from a negative number
2(x) 9 > ?
Third: Divide on each of your sides by the number 2
x - \(\frac{9}{2}\) > ?
Forth: Add the fraction of \(\frac{9}{2}\) to the sides
-.667 (3.0) < ?
Lets just say: 3.0 is a positve while -.667 is a negative
Finally we get to your result
Answer: \(x \ \textgreater \ \frac{9}{2}\)
Good Luck!
