Answer: First Option is correct i.e. \(^9C_3(0.5)^3(0.5)^6\)
Step-by-step explanation:
Since we have given that
Number of times Aron flips a penny = 9 times
Number of heads getting by him exactly = 3
Probability of getting a head (success) is given by
\(\frac{1}{2}\)
Probability of getting a tail ( failure ) is given by
\(\frac{1}{2}\)
So, We need to find the probability of getting exactly 3 heads:
\(P(x=3)=^9C_3(\frac{1}{2})^3\times \frac{1}{2}^6\\\\P(x=3)=^9C_3(0.5)^3\times (0.5)^6\\\\P(x=3)=\frac{9!}{3!\tiems 6!}\times (0.5)^9\\\\P(x=3)=0.16\)
Hence, First Option is correct i.e. \(^9C_3(0.5)^3(0.5)^6\)
