A rectangular pasture has a fence around the perimeter. The length of the fence is 16x^7 and the width is 48x^4. What is the area of the pasture?
A=LW
multily
remmber
\((x^m)(x^n)=x^{m+n}\)
so
\((16x^7)(48x^4)=(16)(x^7)(48)(x^4)=\)\((16)(48)(x^7)(x^4)(768)(x^{7+4})=768x^{11}\)
Answer:
The area of the rectangular pasture is \(768x^{11}\ unit^{2}.\)
Step-by-step explanation:
Formula
Area of a rectangle = Length × Breadth
As given
A rectangular pasture has a fence around the perimeter. The length of the fence is \(16x^{7}\) and the width is \(48x^{4}\).
Put all the values in the formula
\(Area\ of\ a\ rectangular\ pasture = 16x^{7}\times 48x^{4}\)
Now by using the exponent
\(x^{a}\times x^{b} = x^{a+b}\)
\(Area\ of\ a\ rectangular\ pasture = 16\times 48\times (x^{7+4})\)
\(Area\ of\ a\ rectangular\ pasture = 768(x^{11})\)
Therefore the area of the rectangular pasture is \(768x^{11}\ unit^{2}.\)