A rectangular pasture has a fence around the perimeter. The length of the fence is 16x^7 and the width is 48x^4. What is the area of the pasture?

Verified Answer :

A=LW
multily
remmber
\((x^m)(x^n)=x^{m+n}\)
so
\((16x^7)(48x^4)=(16)(x^7)(48)(x^4)=\)\((16)(48)(x^7)(x^4)(768)(x^{7+4})=768x^{11}\)

Answer:

The area of the  rectangular pasture is \(768x^{11}\ unit^{2}.\)

Step-by-step explanation:

Formula

Area of a rectangle = Length ×  Breadth

As given

A rectangular pasture has a fence around the perimeter. The length of the fence is \(16x^{7}\) and the width is \(48x^{4}\).

Put all the values in the formula

\(Area\ of\ a\ rectangular\ pasture = 16x^{7}\times 48x^{4}\)

Now by using the exponent

\(x^{a}\times x^{b} = x^{a+b}\)

\(Area\ of\ a\ rectangular\ pasture = 16\times 48\times (x^{7+4})\)

\(Area\ of\ a\ rectangular\ pasture = 768(x^{11})\)

Therefore the area of the  rectangular pasture is \(768x^{11}\ unit^{2}.\)