If the volume of a sample of gas is increased 5 times the original volume while the temperature is held constant, what happens to the pressure of the gas?

AIt decreases by 1/5.
BIt increases by 1/5.
CIt increases 5 times the original pressure.
DIt stays the same.

Verified Answer :

The answer is C, I hope this answers your question :)

The final pressure of the gas decreases by 1/5 of the original pressure of the gas.

Given:

If the volume of a sample of gas is increased 5 times the original volume while the temperature is held constant,

To find:

The change in pressure of the gas.

Solution:

The initial volume of the gas = \(V_1\)

The initial pressure of the gas = \(P_1\)

The final volume of the gas = \(V_2=5V_1\)

The final pressure of the gas = \(P_2=?\)

Using Boyles law:

\(P_1V_1=P_2V_2\\\\P_2=\frac{P_1V_1}{V_2}\\\\P_2=\frac{P_1V_1}{5V_1}\\\\P_2=\frac{P_1}{5}\)

The final pressure of the gas decreases by 1/5 of the original pressure of the gas.

Learn more about Boyles law here:

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