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The figure is made up of a cone and a cylinder. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box.

The figure is made up of a cone and a cylinder. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter yo class=

Verified Answer :

cerverusdante

Answer

38 m³

Explanation

To solve this we are going to find the volumes of the cylinder and the cone separately, and then we are going to add them.

Volume of the cylinder:

\(V=\pi r^2h\)

where

\(V\) is the volume of the cylinder

\(r\) is the radius

\(h\) is the height

We can infer from the picture that the radius of the cylinder is 3 mm and its height is 2 mm, so let's replace the values

\(V=(3.14) (2mm)^2(2mm)\)

\(V=(3.14)(4mm^2)(2mm)\)

\(V=25.12mm^3\)

Volume of the cone:

\(V=\pi r^2\frac{h}{3}\)

where

\(V\) is the volume of the cone

\(r\) is the radius

\(h\) is the height

We can infer from our picture that the radius of the cone is 4 mm and its height is 3 mm, so let's replace the values

\(V=(3.14)(2mm)^2(\frac{3mm}{3} )\)

\(V=(3.14)(4mm^2)(1m)\)

\(V=12.56mm^3\)

Volume of the figure = area of the cylinder + area of the cone

Volume of the figure = \(25.12mm^3+12.56mm^3=37.68m^3\)

rounded to nearest integer:

Volume of the figure = \(38m^3\)

aksnkj

To, the nearest whole number the approximate volume of this figure will be 63 cubic millimeters.

Given,

The radius of the base of cylinder and cone is 2 mm.

The height of the cylinder is 4 mm.

The height of cone is 3 mm.

We have to find the volume of the figure.

How to calculate the volume of the given shape?

Since the figure is combined of two shapes, a cone and a cylinder.

So we find the volume of each shape separately and add up to find the volume of the whole shape.

We know that volume of cylinder is,

\(V=\pi r^{2} \times h\)

\(V=3.14\times 2^2\times 4\)

\(V=3.14\times 16\)

\(V=50.24 \ mm^3\)

Now the volume of cone is,

\(V'=\dfrac{1}{3} \pi r^{2} \times h\)

\(V'=\dfrac{1}{3} \times 3.14\times 2^2\times 3\)

\(V'= 4 \times 3.14\)\(V'=12.56\ mm^3\)

The volume of the figure will be

\(V+V'=50.24+12.56 \\V+V'=62.80\ mm^3\)

So, the nearest whole number value to this volume is 63 cubic millimeters.

For more details about volume, follow the link:

https://brainly.com/question/4725130

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