Answer:
Step-by-step explanation:
It is given that the base lengths of the trapezoid are \(36 cm\) and \(12\frac{1}{3} cm\) and the height of the trapezoid is \(\sqrt{5} cm\).
Now, the area of the trapezoid is given as:
\(A=\frac{1}{2}(b_{1}+b_{2})h\)
Substituting the given values, we get
\(A=\frac{1}{2}(3.6+12\frac{1}{3})\sqrt{5}\)
\(A=\frac{1}{2}(3.6+\frac{37}{3})\sqrt{5}\)
\(A=\frac{1}{2}(3.6+12.33)\sqrt{5}\)
\(A=\frac{1}{2}(15.93)\sqrt{5}\)
\(A=7.96\sqrt{5} cm^2\)
which is the required area of teh trapezoid.
The area of the trapezoid is irrational because it consists of an irrational term that is \(\sqrt{5}\).
