Verified Answer :

apologiabiology

\(y=ab^x\)



we got
\(3=ab^1\) and
\(20=ab^2\)

divide 2nd equation by first
20/3=(ab^2)/(ab)
20/3=b

sub back

\(3=a \frac{20}{3}^1\)
times both sides by 3/20
9/20=a


\(y= (\frac{9}{20} )( \frac{20}{3})^x\)

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