Jaidee and Eugene are selling fruit for a school fundraiser. Customers can buy small boxes of tangerines and large boxes of tangerines. Jaidee sold 5 small boxes of tangerines and 4 large boxes of tangerines for a total of $130. Eugene sold 2 small boxes of tangerines and 5 large boxes of tangerines for a total of $120. What is the cost each of one small box of tangerines and one large box of tangerines?

Verified Answer :

This is going to take a while. First, set up equations for both Jaidee and Eugene. Jaidee's equation is \(5s+4l=130\)  s represents the cost of the small box of tangerines and \(l\) represents the cost of the large box of tangerines. Eugene's equation is \(2s+5l=120\) .  Next, I'm going to solve the equations through elimination. Multiply -2 by the first equation and multiply 5 by the second equation. \(-2(5s+4l=130)=-10s-8l=-260\)  Do the same for the second equation. \(5(2s+5l=120)=10s+25l=600\) . Then add \(10s-8l=-260+10s+25l=600\)  This gives you \(17l=340\) . Next divide on both sides  \(\frac{17l}{17} =\frac{340}{17}\)  this will give you \(l=20\) . So you know what \(l\) is. Next, plug in \(l\) to \(10s+25l=600\) which looks like this \(10s+25(20)=600\). Solve 10s+500=600

= 10s+500-500=600-500

=10s=100

= 10s/10=100/10

= s=10 . So each box of small tangerines costs $10 and each box of large tangerines cost $20.