This is going to take a while. First, set up equations for both Jaidee and Eugene. Jaidee's equation is \(5s+4l=130\) s represents the cost of the small box of tangerines and \(l\) represents the cost of the large box of tangerines. Eugene's equation is \(2s+5l=120\) . Next, I'm going to solve the equations through elimination. Multiply -2 by the first equation and multiply 5 by the second equation. \(-2(5s+4l=130)=-10s-8l=-260\) Do the same for the second equation. \(5(2s+5l=120)=10s+25l=600\) . Then add \(10s-8l=-260+10s+25l=600\) This gives you \(17l=340\) . Next divide on both sides \(\frac{17l}{17} =\frac{340}{17}\) this will give you \(l=20\) . So you know what \(l\) is. Next, plug in \(l\) to \(10s+25l=600\) which looks like this \(10s+25(20)=600\). Solve 10s+500=600
= 10s+500-500=600-500
=10s=100
= 10s/10=100/10
= s=10 . So each box of small tangerines costs $10 and each box of large tangerines cost $20.