Answer:
1.9902 nano meter is the wavelength of the detected radiation.
Explanation:
\(E=\frac{hc}{\lambda}\)
\(\lambda\) = Wavelength of radiation
E= energy of the photon of the wave
h = Planck's constant = \(6.634\times 10^{-34}Js\)
c = speed of light = \(3\times 10^8m/s\)
\(\lambda = \frac{hc}{E}\)
Energy of the radiations = E = \(1.00\times 10^{-16} J\)
\(=\frac{6.634\times 10^{-34}Js\times 3\times 10^8 m/s}{1.00\times 10^{-16} J}\)
\(\lambda =19.902\times 10^{-10}m=1.9902 nm\)
\(1 m = 10^9 nm\)
