If the measure of an intercepted arc is 118°, and the measure of the inscribed angle is 2x - 1, what is the equation to find the value of x?
By using the inscribed angle and intercepted arc relationship, the equation to find the value of x is \(4x-2 = 118^{0}\)
The measure of an inscribed angle is half the measure of the intercepted arc.
i.e., m<ABC = \(\frac{1}{2}\) m<AOC
Given
Measure of an intercepted arc = \(118^{0}\)
Measure of an inscribed angle = 2x - 1
m<ABC = \(\frac{1}{2}\) m<AOC
Substitute values in above formula
⇒\(\frac{1}{2} (118)^{0}\) = \((2x-1)\)
⇒ \(4x-2 = 118^{0}\)
Hence, By using the inscribed angle and intercepted arc relationship, the equation to find the value of x is \(4x-2 = 118^{0}\)
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