\(\bf f(x)=2x^2-3x+15\qquad f(0.5)\qquad
\begin{cases}
0.5\iff \frac{1}{2}
\end{cases}
\\\\
\textit{let us use }\frac{1}{2}
\\\\
f\left( \frac{1}{2} \right)=2\left( \frac{1}{2} \right)^2-3\left( \frac{1}{2} \right)+15\to 2\cdot \cfrac{1^2}{2^2}-\cfrac{3}{2}+15\to 2\cdot \cfrac{1}{4}-\cfrac{3}{2}+15
\\\\\\
f\left( \frac{1}{2} \right)=\cfrac{1}{2}-\cfrac{3}{2}+15\to -\cfrac{2}{2}+15\to -1+15\to 14\)
