Verified Answer :

texaschic101

(4/5,1/5)(1/2,3/2)
slope = (3/2 - 1/5) / (1/2 - 4/5) = (15/10 - 2/10) / (5/10 - 8/10) = (13/10) / (- 3/10) = 13/10 * - 10/3 = - 130/30 reduces to -13/3

y = mx + b
slope(m) = -13/3
use either of ur points (4/5,1/5)....x = 4/5 and y = 1/5
now we sub and find b, the y int
1/5 = -13/3(4/5) + b
1/5 = - 52/15 + b
1/5 + 52/15 = b
3/15 + 52/15 = b
55/15 (reduces to 11/3) = b

so ur equation is : y = -13/3x + 11/3 <==

apologiabiology

y-y1=m(x-x1)
that is the equation of a line that passes through the point (x1,y1) and has a slope of m


slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so first convert them to common denomenator which is 10

\(( \frac{8}{10} , \frac{2}{10} )\) and \(( \frac{5}{10} , \frac{15}{10} )\)
slope=\(\frac{\frac{15}{10}-\frac{2}{10}}{ \frac{5}{10}-\frac{8}{10} } = \frac{\frac{13}{10}}{ \frac{-3}{10} } = \frac{13}{-3}= \frac{-13}{3}\)

a point is \(( \frac{1}{2} , \frac{3}{2} )\)

so
\(y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})\)
\(y-\frac{3}{2}=\frac{-13}{3}x+\frac{13}{6}\)
times both sides by 6
\(6y-9=-26x+13\)
\(6y=-26x+22\)
\(y= \frac{-13}{3}x+ \frac{11}{3}\) or in standard form

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