Answer:
291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.
Explanation:
Molarity of teh HCl solution = 5.0 M
Volume of HCl solution = 4.8 L
\(Molarity=\frac{\text{Number of moles Moles}}{\text{Volume of the solution (L)}}\)
\(5.0 M=\frac{Moles}{4.8 L}\)
Moles of HCl = 24 moles
\(Mg+2HCL\rightarrow MgCl_2+H_2\)
According to reaction , 2 moles of HCl reacts with 1 mole magnesium.
Then 24 moles of HCl will react with:
\(\frac{1}{2}\times 24 mol=12 mol\) of magnesium
Mass of 12 mol of magnesium =24.31 g/mol × 12 mol = 291.72 g
291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.
