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If the thermal energy of the system increases by 600 jewels and 1400 J of heat were added to the system how much work did the system do


600J


800J


1,400J


2,000J

Verified Answer :

Answer: The work done by the system is 800 Joules.

Explanation:

Internal change in thermal energy of the system,\(\Delta U\)= 600 Joules

Energy added to the system the system,Q = 1400 Joules

Work done by the system can be calculated by using First law of thermodynamics:'

\(\Delta U=Q-W\) (First law of thermodynamics)

\(600 J=1400 J-W\)

\(W=Q-\Delta U=1400 J-600 J=800 J\)

The work done by the system is 800 Joules.

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THE ANSWER IS DOWN BELOW :)

Explanation:

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