\(\bf \begin{array}{ccllll}
days&miles\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1&\frac{6}{4}\\\\
x&3
\end{array}\implies \cfrac{1}{x}=\cfrac{\frac{6}{4}}{3}\)
solve for "x"