Answered

A 75.0 kg sailor climbs a 28.3 m rope ladder at and angle of 45.0degrees with the mast. how much work did he do?

Verified Answer :

W = m · g · h
h = 28.3 m · sin 45° = 28.3 m · 0.707 = 20 m
g = 9.8 m/s²
W = 75 kg · 9.8 m/s² · 20 m
Answer:
W = 14,700 J = 14.7 kJ 

The work done by the sailor is 14,700 J. Work can be defined as a change in energy.

How to calculate the work?

The can be calculated by multiplying the force with displacement.

\(W = F d\)

Where,

\(F\) - force = \(mg\) = 75 kg x 9.8 = 735 N

\(d\) - displacement = \(h\) (height)

First, calculate the displacement :

\(h\) = 28.3 m · sin 45°

\(h\)= 28.3 m · 0.707

\(h\) = 20 m

Put the values in the formula,

W = 735 x 20

W = 14,700 J

Therefore, the work done by the sailor is 14,700 J.

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