Answer:
\((3 \pi+12)\ mm\)
Step-by-step explanation:
we know that
The perimeter of the figure is equivalent to the perimeter of a rectangle plus the perimeter of semicircle minus the length side of \(6\) mm
step 1
Find the perimeter of rectangle
the perimeter of rectangle is equal to
\(P=2(b+h)\)
we have
\(b=6\ mm\)
\(h=3\ mm\)
substitute
\(P=2(6+3)=18\ mm\)
step 2
Find the circumference of semicircle
the of circumference of semicircle is equal to
\(C=\frac{1}{2}\pi D\)
we have
\(D=6\ mm\)
substitute
\(C=\frac{1}{2}\pi (6)=3 \pi\ mm\)
step 3
Find the perimeter of the figure
\(18\ mm+3 \pi\ mm-6\ mm=(3 \pi+12)\ mm\)
