Verified Answer :
Answer:
Required Probability=\(\frac{^{6670}C_{20}}{^{40000}C_{20}}\)
Step-by-step explanation:
We have been given the total 40,000 words
And the words that started with letter T is 6,670
We need to find the probability of the words beginning with T
Words beginning with T will be \(^{6670}C_{20}\)
Total words after choosing 20 unique words would be: \(^{40000C_{20}\)
\(Probability=\frac{\text{words beginning with T}}{\text{total words}}\)
\(Probability=\frac{^{6670}C_{20}}{^{40000}C_{20}}\)
Hence,
Required Probability=\(\frac{^{6670}C_{20}}{^{40000}C_{20}}\)
Answer:
\(\frac{^{6670}C_{20}}{^{40000}C_{20}}\)
Step-by-step explanation:
Given : A study conducted on 40,000 words in the English language found that about 6,670 words started with the letter T, which is the most common letter to start a word.
To Find: If we randomly pick 20 unique words, which of these lists of words will come closest to the theoretical probability of getting a word beginning with T?
Solution:
There are 6670 words starting from T
They randomly select 20 words
So, the possible outcomes starting from T : \(^{6670}C_{20}\)
Since 20 words are selected from the total of 40000: \(^{40000}C_{20}\)
So, probability of getting a word beginning with T : \(\frac{^{6670}C_{20}}{^{40000}C_{20}}\)