This question involves the concepts of percent composition and atomic mass.
The percent composition of sulfur in H₂SO₄ is "A. 32.7 %".
First, we will find out the total mass of H₂SO₄ molecule:
Total Mass = 2(atomic mass of H) + (atomic mass of sulfur) + 4(atomic mass of O)
Total Mass = 2(1 g) + (32 g) + 4(16 g)
Total Mass = 98 g
Now, for percent composition of sulfur:
Percent Composition of Sulphur = \(\frac{atomic\ mass\ of\ sulphur}{total\ mass}(100\%)\)
Percent Composition of Sulphur =\(\frac{32\ g}{98\ g}(100\%)\)
Percent Composition of Sulphur = 32.7 %
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