Find the equation of the line that has a slope of 3 and passes through the point (-5,4)
we can use point-slope form (since we have the slope, and 1 ordered pair)
point-slope form is y-y1=m(x-x1)
x=-5
y=4
m=3
y-(4)=3(x-(-5)
our point-slope formula isĀ \((y- y_{1} )=m(x-x_{1})\)
m=slope
\(x_{1} = -5\)
\(y_{1} =4\)
Therefor, when we input our values and simplify, we get...
\((y-(4))=3(x-(-5) \\ y-4=3x+15 \\ y=3x+19\)