Answer:
Hence, the population of deer in the year 2013 will be:
2180.
Step-by-step explanation:
It is given that:
The population of deer in a forest was measured to be 1,938 in the year 2010.
If the population increased by a steady rate of 4% per year.
Let P(t) denotes the population of the deer in the forest in 't' years.
This means that the population function P(t) can be defined as:
\(P(t)=1938\times (1+0.04)^t\)
i.e. in the year 2010 let t=0.
in the year 2011 let t=1.
in the year 2012 t=2
and in the year 2013, t=3
Hence, the population of the deer in the year 2013 is given by:
\(P(t)=1938\times (1+0.04)^3\\\\P(t)=1938\times (1.04)^3\\\\\\P(t)=2179.98\)
which is approximately given as:
\(P(t)=2180\)
Hence, the population of deer in the year 2013 will be:
2180.
