4d+15less then or = to -1
4d + 15d ≤ -1 : ∑ Solution: Interval Notation: ( d ≤ -4 -∞, -4 ]Steps4d + 15 ≤ -1-----------------Subtract 15 from both sides4d + 15 -15 ≤ -1 - 15Refine4d ≤ -16Divide both sides by 44d/4 ≤ -16/4Refined ≤ -4