From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I know the answer is 15 ways , but how do you do it ? 30 points
This is a combination problem.
6 nCr 2
\(\frac{6!}{2! * (6-2)!} = \frac{720}{48}=15\)
Answer:
15
Step-by-step explanation:
Here we have to use the combination formula.
nCr = n! / r! (n - r)!
Given: n = 6 and r = 2
Plugging in the given values, we get
6C2 = 6! / 2!(6 - 2)!
= 6! / 2! 4!
6! = 123456 = 720
4! = 1234 = 24
2! = 12 = 2
6C2 = 720 / 224
= 720/48
= 15
We can select in 15 different ways.
Hope this will helpful.
Thank you.