Given that A = 42°, B = 56°, and a = 7, solve triangle ABC. Round the answers to the nearest hundredth, if necessary.

AC=82°, b=3.92, c=10.36

BC=2°, b=3.92, c=10.36

CC=2°, b=8.67, c=10.36

DC=82°, b=8.67, c=10.36

Verified Answer :

Answer:

Option D is correct.

Step-by-step explanation:

Given,

In ΔABC, ∠A = 42° , ∠B = 56° & a = 7

We use law of sines,

which has following expression:

\(\frac{a}{sin\,A}=\frac{b}{sin\,B}\frac{c}{sin\,C}\)

First we find value of ∠C

∠A + ∠B + ∠C = 180°   (Angle Sum Property of Triangle)

42 + 56 + ∠C = 180

∠C = 180 - 98

∠C = 82°

Now using law of sines, we get

\(\frac{7}{sin\,42}=\frac{b}{sin\,56}\)

\(\frac{7}{0.67}=\frac{b}{0.83}\)

\(b=\frac{7}{0.67}\times0.83\)

\(b=8.67\)

\(\frac{7}{sin\,42}=\frac{c}{sin\,82}\)

\(\frac{7}{0.67}=\frac{c}{0.99}\)

\(c=\frac{7}{0.67}\times0.99\)

\(c=10.36\)

Therefore, Option D is correct.