Verified Answer :

Moles of MgS2O3 = 223/molar mass of MgS2O3
    
                              =   223/136.42 
                              =     1.634 moles.

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Answer: 1.63 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\)

Given mass = 223 g

Molar mass = 136.4

\(\text{Number of moles}=\frac{223g}{136.4g/mol}=1.63moles\)

Thus there are 1.63 moles in 223 g of the compound.