so.. check the picture, notice the length
then \(\bf Area=l\times w\qquad
\begin{cases}
l=2w-3\\
Area=65
\end{cases}\\\\
-----------------------------\\\\
thus
\\\\
65=(2w-3)\times w\)
solve for "w" to get the width,
what's the length? well, l = 2w-3
