Answer:
The vertex form of a quadratic function is given by \(y = a(x - h)^2 + k\) , where (h, k) is the vertex of the parabola.
Given the function :
g(x) = \(4x^2+88x\)
g(x) = \(4(x^2+22x)\)
Now, we will be completing the square ;
g(x) = \(4(x^2+22x+11^2-11^2)\) = \(4(x^2+88x+11^2)-4 \cdot(11^2)\)
⇒ g(x) =\(4 (x+11)^2 -4 \cdot 121\) or
\(g(x) =4(x+11)^2 - 484\)
therefore, the given function is in the vertex form is, \(g(x) =4(x+11)^2 +(-484)\)
