Answer:
the altitude of the plane to the nearest foot is, 277 feet high
Step-by-step explanation:
Using tangent ratio:
\(\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}\)
As per the statement:
The glide slope usually makes a 3º angle with the ground.
⇒\(\theta = 3^{\circ}\)
A plane is on the glide slope and is 1 mile (5280 feet) from touchdown.
⇒Adjacent side= DF = 1 mi = 5280 feet.
We have to find the EF.
Using tangent ratio:
\(\tan \theta^{\circ}= \frac{\text{EF}}{\text{DF}}\)
Substitute the given values we have;
\(\tan 3^{\circ}= \frac{\text{EF}}{5280}\)
Multiply both sides by 5280 we have;
\(\text{EF} = 5280 \cdot \tan 3^{\circ}\)
⇒\(\text{EF} = 5280 \cdot 0.05240777928\)
Simplify:
EF = 276.713074614 feet.
Therefore, the altitude of the plane to the nearest foot is, 277 feet high
