André solves the following system of equations by elimination.
3a+6b=12
-3a+6b=-12
What is the resulting equation?
12b = 0
6a = 0
–6a = 0
–12b = –24
3a+6b=12
-3a+6b=-12
What is the resulting equation?
12b = 0
6a = 0
–6a = 0
–12b = –24