A cube of plastic 1.2x10^-5 km on a side has a mass of 1.1 g. what is its density in g/cm^3
length of 1 side 1.210^-5km =1.210^-5*10^5 =1.2cm
volume of the cube (1.2)^3=1.728 cm^3
density= mass/volume= 1.1/1.728=0.636 g/cm^3
Answer:
\(0.6366 g/cm^3\) is the density of the cubic plastic.
Explanation:
Mass of the cubic block= m = 1.1 g
Volume of the cubic block = V
Volume of the cube = \(a^3\)
a = side length = \(1.2\times 10^{-5} km = 1.2 cm\)
1 km = 100,000 cm
Volume of cubic block = \(V=(12 cm)^3=1.728 cm^3\)
Density of the solid block,d = ?
\(Density=\frac{Mass}{Volume}\)
\(d=\frac{m}{V}=\frac{1.1 g}{1.728 cm^3}=0.6366 g/cm^3\)
\(0.6366 g/cm^3\) is the density of the cubic plastic.