simplify the expression 2m over 8(m+n)
\(\frac{2m}{8(m+n)}= \frac{(2)(m)}{(2)(4(m+n))}=( \frac{2}{2} )( \frac{m}{4(m+n)} )= (1)(\frac{m}{4(m+n)} )=\frac{m}{4(m+n)}\)
