Verified Answer :

dexteright02

Data:
v (volume) = ?
h (height) = 10 m
r (radius) = 5 m
Adopting: \(\pi \approx 3.14\)

Formula:
\(V = h* \pi *r^2\)

Solving:
\(V = h* \pi *r^2\)
\(V = 10*3.14*5^2\)
\(V = 10*3.14*25\)
\(\boxed{V=785\:m^3}}\end{array}\)

If:

785 m³ → 100%
y m³ → 75%

Solving: Rule of three (directly proportional)
\(\frac{785}{y} = \frac{100}{75}\)
multiply cross
\(100*y = 785*75\)
\(100y = 58875\)
\(y = \frac{58875}{100}\)
\(\boxed{\boxed{y = 588.75\:m^3}}\end{array}}\qquad\quad\checkmark\)

Answer:
The volume of water that the tank contains when it is 75% full is 588.75 m³

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