Answer: The value of \(3a^2+4b^2\) is 48.
Step-by-step explanation:
Since we have given that
\(3a^2+4b^2\)
Here, a = 2
b = 3
So, we put the values of a and b in given expression:
So, Value of above expression would be
\(3(2)^2+4(3)^2\\\\3\times 4+4\times 9\\\\=12+36\\\\=48\)
Hence, the value of \(3a^2+4b^2\) is 48.
