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lmaldonado83 lmaldonado83
  • 14-02-2017
  • Chemistry
Answered

The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

Verified Answer :

Edufirst
Edufirst Edufirst
  • 21-02-2017

The ionization equation is:

HF ⇄ H(+) + F(-)

The ionization constant is Ka = [H(+)] [H(-)] / [HF]

=> [H(+)] [F(-)] = Ka [HF]

Given that Ka < 1

[H(+)] [F(-)] < [HF]

Which is [HF] >  [H(+)] * [F(-)] the option a. fo the list of choices.

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