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radio signals travel at a rate of 3x10^8 meters per second. how many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 3.6x10^7


1.) 8.3 seconds

2.) 10.8 x 10^15 seconds

3.) 1.2 x 10^-1 seconds

4.) 1.08 x 10^16 seconds


thank you!! c:

Verified Answer :

time = distance/speed

\(T = \frac{3.6 \times 10^7}{3 \times 10^8}= \boxed{1.2 \times 10^{-1} sec}\)

Answer:

Option 3

The time taken for a radio signal to travel from a satellite to the surface of the Earth is \(1.2\times10^{-1}\)

Step-by-step explanation:

Given : Radio signals travel at a rate of \(3\times10^8\) meters per second. The satellite is orbiting at a height of \(3.6\times10^7\).

To find : How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth?

Solution :

The speed of radio signal is  \(3\times10^8\) meters per second.

The distance or height of satellite orbiting is \(3.6\times10^7\).

\(\text{Time}=\frac{\text{Distance}}{\text{Speed}}\)

Substitute the value in the formula,

\(\text{Time}=\frac{3.6\times10^7}{3\times10^8}\)

\(\text{Time}=1.2\times10^{-1}\)

Therefore, Option 3 is correct.

The time taken for a radio signal to travel from a satellite to the surface of the Earth is \(1.2\times10^{-1}\)

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