beautifulmaryam beautifulmaryam

14-02-2017
Mathematics

Answered

How many and what type of solutions does the equation have? 2k² = 9 + 3k

Verified Answer :

Anonymous Anonymous

14-02-2017

2k² = 9 + 3k

⇒ 2k² - 9 - 3k
= 0
⇒ 2k² - 3k -9 = 0

b² - 4ac = 3² - 42(-9) = 81>0

It has 2 real roots.

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