Answer:
The simplest radical form of \(\frac{-1}{x^{\frac{-3}{6}}}\) is -√x.
Step-by-step explanation:
Consider the provided expression.
\(\frac{-1}{x^{\frac{-3}{6}}}\)
The above expression can be written as:
\(\frac{-1}{x^{\frac{-1}{2}}}\)
Now use the negative exponent rule: \(\frac{1}{x^{-n}}=x^n\)
By using the above rule:
\(-1\times x^{\frac{1}{2}\)
\(-1\times \sqrt{x}\)
\(-\sqrt{x}\)
Hence, the simplest radical form of \(\frac{-1}{x^{\frac{-3}{6}}}\) is -√x.
