Answer : The amount of heat needed are, 8464.5 J
Explanation :
Formula used :
\(q=m\times c\times (T_{final}-T_{initial})\)
where,
q = heat gained = ?
m = mass of water = 45.0 g
c = specific heat of water = \(4.18J/g^oC\)
\(T_{final}\) = final temperature = \(75.0^oC\)
\(T_{initial}\) = initial temperature = \(30.0^oC\)
Now put all the given values in the above formula, we get:
\(q=45.0g\times 4.18J/g^oC\times (75.0-30.0)^oC\)
\(q=8464.5J\)
Thus, the amount of heat needed are, 8464.5 J
